3.994 \(\int x^m (3-2 a x)^{-2+n} (6+4 a x)^n \, dx\)

Optimal. Leaf size=158 \[ \frac {2^n 9^{n-1} x^{m+1} \, _2F_1\left (\frac {m+1}{2},2-n;\frac {m+3}{2};\frac {4 a^2 x^2}{9}\right )}{m+1}+\frac {a 2^{n+2} 3^{2 n-3} x^{m+2} \, _2F_1\left (\frac {m+2}{2},2-n;\frac {m+4}{2};\frac {4 a^2 x^2}{9}\right )}{m+2}+\frac {a^2 2^{n+2} 9^{n-2} x^{m+3} \, _2F_1\left (\frac {m+3}{2},2-n;\frac {m+5}{2};\frac {4 a^2 x^2}{9}\right )}{m+3} \]

[Out]

2^n*9^(-1+n)*x^(1+m)*hypergeom([2-n, 1/2+1/2*m],[3/2+1/2*m],4/9*a^2*x^2)/(1+m)+2^(2+n)*3^(-3+2*n)*a*x^(2+m)*hy
pergeom([2-n, 1+1/2*m],[2+1/2*m],4/9*a^2*x^2)/(2+m)+2^(2+n)*9^(-2+n)*a^2*x^(3+m)*hypergeom([2-n, 3/2+1/2*m],[5
/2+1/2*m],4/9*a^2*x^2)/(3+m)

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Rubi [A]  time = 0.11, antiderivative size = 158, normalized size of antiderivative = 1.00, number of steps used = 8, number of rules used = 3, integrand size = 22, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.136, Rules used = {127, 125, 364} \[ \frac {2^n 9^{n-1} x^{m+1} \, _2F_1\left (\frac {m+1}{2},2-n;\frac {m+3}{2};\frac {4 a^2 x^2}{9}\right )}{m+1}+\frac {a 2^{n+2} 3^{2 n-3} x^{m+2} \, _2F_1\left (\frac {m+2}{2},2-n;\frac {m+4}{2};\frac {4 a^2 x^2}{9}\right )}{m+2}+\frac {a^2 2^{n+2} 9^{n-2} x^{m+3} \, _2F_1\left (\frac {m+3}{2},2-n;\frac {m+5}{2};\frac {4 a^2 x^2}{9}\right )}{m+3} \]

Antiderivative was successfully verified.

[In]

Int[x^m*(3 - 2*a*x)^(-2 + n)*(6 + 4*a*x)^n,x]

[Out]

(2^n*9^(-1 + n)*x^(1 + m)*Hypergeometric2F1[(1 + m)/2, 2 - n, (3 + m)/2, (4*a^2*x^2)/9])/(1 + m) + (2^(2 + n)*
3^(-3 + 2*n)*a*x^(2 + m)*Hypergeometric2F1[(2 + m)/2, 2 - n, (4 + m)/2, (4*a^2*x^2)/9])/(2 + m) + (2^(2 + n)*9
^(-2 + n)*a^2*x^(3 + m)*Hypergeometric2F1[(3 + m)/2, 2 - n, (5 + m)/2, (4*a^2*x^2)/9])/(3 + m)

Rule 125

Int[((f_.)*(x_))^(p_.)*((a_.) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_.), x_Symbol] :> Int[(a*c + b*d*x^2)
^m*(f*x)^p, x] /; FreeQ[{a, b, c, d, f, m, n, p}, x] && EqQ[b*c + a*d, 0] && EqQ[m - n, 0] && GtQ[a, 0] && GtQ
[c, 0]

Rule 127

Int[((f_.)*(x_))^(p_.)*((a_.) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_.), x_Symbol] :> Int[ExpandIntegrand
[(a + b*x)^n*(c + d*x)^n*(f*x)^p, (a + b*x)^(m - n), x], x] /; FreeQ[{a, b, c, d, f, m, n, p}, x] && EqQ[b*c +
a*d, 0] && IGtQ[m - n, 0] && NeQ[m + n + p + 2, 0]

Rule 364

Int[((c_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Simp[(a^p*(c*x)^(m + 1)*Hypergeometric2F1[-
p, (m + 1)/n, (m + 1)/n + 1, -((b*x^n)/a)])/(c*(m + 1)), x] /; FreeQ[{a, b, c, m, n, p}, x] &&  !IGtQ[p, 0] &&
(ILtQ[p, 0] || GtQ[a, 0])

Rubi steps

\begin {align*} \int x^m (3-2 a x)^{-2+n} (6+4 a x)^n \, dx &=\int \left (36 x^m (3-2 a x)^{-2+n} (6+4 a x)^{-2+n}+48 a x^{1+m} (3-2 a x)^{-2+n} (6+4 a x)^{-2+n}+16 a^2 x^{2+m} (3-2 a x)^{-2+n} (6+4 a x)^{-2+n}\right ) \, dx\\ &=36 \int x^m (3-2 a x)^{-2+n} (6+4 a x)^{-2+n} \, dx+(48 a) \int x^{1+m} (3-2 a x)^{-2+n} (6+4 a x)^{-2+n} \, dx+\left (16 a^2\right ) \int x^{2+m} (3-2 a x)^{-2+n} (6+4 a x)^{-2+n} \, dx\\ &=36 \int x^m \left (18-8 a^2 x^2\right )^{-2+n} \, dx+(48 a) \int x^{1+m} \left (18-8 a^2 x^2\right )^{-2+n} \, dx+\left (16 a^2\right ) \int x^{2+m} \left (18-8 a^2 x^2\right )^{-2+n} \, dx\\ &=\frac {2^n 9^{-1+n} x^{1+m} \, _2F_1\left (\frac {1+m}{2},2-n;\frac {3+m}{2};\frac {4 a^2 x^2}{9}\right )}{1+m}+\frac {2^{2+n} 3^{-3+2 n} a x^{2+m} \, _2F_1\left (\frac {2+m}{2},2-n;\frac {4+m}{2};\frac {4 a^2 x^2}{9}\right )}{2+m}+\frac {2^{2+n} 9^{-2+n} a^2 x^{3+m} \, _2F_1\left (\frac {3+m}{2},2-n;\frac {5+m}{2};\frac {4 a^2 x^2}{9}\right )}{3+m}\\ \end {align*}

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Mathematica [A]  time = 0.13, size = 172, normalized size = 1.09 \[ \frac {9^{n-2} x^{m+1} \left (36-16 a^2 x^2\right )^n \left (18-8 a^2 x^2\right )^{-n} \left (9 \left (m^2+5 m+6\right ) \, _2F_1\left (\frac {m+1}{2},2-n;\frac {m+3}{2};\frac {4 a^2 x^2}{9}\right )+4 a (m+1) x \left (3 (m+3) \, _2F_1\left (\frac {m+2}{2},2-n;\frac {m+4}{2};\frac {4 a^2 x^2}{9}\right )+a (m+2) x \, _2F_1\left (\frac {m+3}{2},2-n;\frac {m+5}{2};\frac {4 a^2 x^2}{9}\right )\right )\right )}{(m+1) (m+2) (m+3)} \]

Antiderivative was successfully verified.

[In]

Integrate[x^m*(3 - 2*a*x)^(-2 + n)*(6 + 4*a*x)^n,x]

[Out]

(9^(-2 + n)*x^(1 + m)*(36 - 16*a^2*x^2)^n*(9*(6 + 5*m + m^2)*Hypergeometric2F1[(1 + m)/2, 2 - n, (3 + m)/2, (4
*a^2*x^2)/9] + 4*a*(1 + m)*x*(3*(3 + m)*Hypergeometric2F1[(2 + m)/2, 2 - n, (4 + m)/2, (4*a^2*x^2)/9] + a*(2 +
m)*x*Hypergeometric2F1[(3 + m)/2, 2 - n, (5 + m)/2, (4*a^2*x^2)/9])))/((1 + m)*(2 + m)*(3 + m)*(18 - 8*a^2*x^
2)^n)

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fricas [F]  time = 1.14, size = 0, normalized size = 0.00 \[ {\rm integral}\left ({\left (4 \, a x + 6\right )}^{n} {\left (-2 \, a x + 3\right )}^{n - 2} x^{m}, x\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^m*(-2*a*x+3)^(-2+n)*(4*a*x+6)^n,x, algorithm="fricas")

[Out]

integral((4*a*x + 6)^n*(-2*a*x + 3)^(n - 2)*x^m, x)

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giac [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int {\left (4 \, a x + 6\right )}^{n} {\left (-2 \, a x + 3\right )}^{n - 2} x^{m}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^m*(-2*a*x+3)^(-2+n)*(4*a*x+6)^n,x, algorithm="giac")

[Out]

integrate((4*a*x + 6)^n*(-2*a*x + 3)^(n - 2)*x^m, x)

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maple [F]  time = 0.16, size = 0, normalized size = 0.00 \[ \int x^{m} \left (-2 a x +3\right )^{n -2} \left (4 a x +6\right )^{n}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^m*(-2*a*x+3)^(n-2)*(4*a*x+6)^n,x)

[Out]

int(x^m*(-2*a*x+3)^(n-2)*(4*a*x+6)^n,x)

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maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int {\left (4 \, a x + 6\right )}^{n} {\left (-2 \, a x + 3\right )}^{n - 2} x^{m}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^m*(-2*a*x+3)^(-2+n)*(4*a*x+6)^n,x, algorithm="maxima")

[Out]

integrate((4*a*x + 6)^n*(-2*a*x + 3)^(n - 2)*x^m, x)

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mupad [F]  time = 0.00, size = -1, normalized size = -0.01 \[ \int x^m\,{\left (3-2\,a\,x\right )}^{n-2}\,{\left (4\,a\,x+6\right )}^n \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^m*(3 - 2*a*x)^(n - 2)*(4*a*x + 6)^n,x)

[Out]

int(x^m*(3 - 2*a*x)^(n - 2)*(4*a*x + 6)^n, x)

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sympy [F(-1)]  time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x**m*(-2*a*x+3)**(-2+n)*(4*a*x+6)**n,x)

[Out]

Timed out

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